How about 1/(x \* ∞)? Only works if you allow (0 \* ∞) = 1, which is admittedly ... | Hacker News

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		nemo1618 on June 25, 2016 \| parent \| context \| favorite \| on: A Quirky Function How about 1/(x * ∞)? Only works if you allow (0 * ∞) = 1, which is admittedly quite shaky.

majewsky on June 25, 2016 [–]

All arithmetic with +/- ∞ is shaky. But even then, your solution is wrong because it's defined on negative numbers.

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