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oneloop
on Aug 1, 2016
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Surprises of the Faraday Cage
epsilon log(r) is the "shielding". I suspect that the field inside will be attenuated by a factor of 1/(epsilon log(r)).
Panoramix
on Aug 1, 2016
[–]
epsilon is the gap, so either way it should be on opposite side of the log(r). Smaller gap, stronger shielding but smaller radius weaker shielding. Am I going nuts?
oneloop
on Aug 1, 2016
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Hm I guess you're right. I don't know what to tell you. I guess we'd have to have a look at the exact definitions they use in the paper :-)
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