So the analogy with the Krein–Milman theorem would be this: Any proof is (approx... | Hacker News

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		hanche on April 14, 2020 \| parent \| context \| favorite \| on: John Conway So the analogy with the Krein–Milman theorem would be this: Any proof is (approximately, at least) a combination of the extreme proofs of the same result? Now I have to go read the paper referred to.

vladislav on April 14, 2020 [–]

I don't think it was meant so literally. just an interesting way of calling someone a unique mathematician

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