For a sequence of n numbers, fit an n-1 degree polynomial on (0, v_0), (1, v_1), ..., and compute for n. Doesn't even have to a polynomial. Any independent function base will do, I suppose. And who can contradict you?
Doesn't really matter what "mathologer" thinks the next number is.
Doesn't really matter what "mathologer" thinks the next number is.