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		dllthomas on Aug 18, 2014 \| parent \| context \| favorite \| on: We have C++14 But the expanded form does provide you with more flexibility. Even if the latter is a synonym for the former, there is a difference between: `template<typename T> void foo(T a, T b)` vs `void foo(auto a, auto b)`

kazinator on Aug 18, 2014 [–]

It seems like in the second `foo`, the types of `a` and `b` are not hinged together. So to do it with the template syntax you actually need:

    template<typename T, typename U>
    void foo(T a, U b)

:)

dllthomas on Aug 19, 2014 | [–]

I intended the two to share a type. My point was that you cannot express that constraint with only auto.

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